[LeetCode] 175.Combine Two Tables 聯(lián)合兩表

Table: Person

+-------------+---------+
| Column Name | Type    |
+-------------+---------+
| PersonId    | int     |
| FirstName   | varchar |
| LastName    | varchar |
+-------------+---------+
PersonId is the primary key column for this table.

Table: Address

+-------------+---------+
| Column Name | Type    |
+-------------+---------+
| AddressId   | int     |
| PersonId    | int     |
| City        | varchar |
| State       | varchar |
+-------------+---------+
AddressId is the primary key column for this table.

Write a SQL query for a report that provides the following information for each person in the Person table, regardless if there is an address for each of those people:

FirstName, LastName, City, State

LeetCode還出了是來到數(shù)據(jù)庫的題，來那么也來做做吧，這道題是第一道，相對來說比較簡單，是一道兩表聯(lián)合查找的問題，我們需要用到Join操作，關(guān)于一些Join操作可以看我之前的博客SQL Left Join, Right Join, Inner Join, and Natural Join 各種Join小結(jié)，最直接的方法就是用Left Join來做，根據(jù)PersonId這項來把兩個表聯(lián)合起來：

解法一：

SELECT Person.FirstName, Person.LastName, Address.City, Address.State FROM Person LEFT JOIN Address ON Person.PersonId = Address.PersonId;

在使用Left Join時，我們也可以使用關(guān)鍵Using來聲明我們相用哪個列名來進行聯(lián)合：

解法二：

SELECT Person.FirstName, Person.LastName, Address.City, Address.State FROM Person LEFT JOIN Address USING(PersonId);

或者我們可以加上Natural關(guān)鍵字，這樣我們就不用聲明具體的列，MySQL可以自行搜索相同的列：

解法三：

SELECT Person.FirstName, Person.LastName, Address.City, Address.State FROM Person NATURAL LEFT JOIN Address;

參考資料：

https://leetcode.com/discuss/21216/its-a-simple-question-of-left-join-my-solution-attached

https://leetcode.com/discuss/53001/comparative-solution-between-left-using-natural-left-join

到此這篇關(guān)于SQL實現(xiàn)LeetCode(175.聯(lián)合兩表)的文章就介紹到這了,更多相關(guān)SQL實現(xiàn)聯(lián)合兩表內(nèi)容請搜索腳本之家以前的文章或繼續(xù)瀏覽下面的相關(guān)文章希望大家以后多多支持腳本之家！