一、接收固定長度的參數
復制代碼 代碼如下:
[root@svn shell_example]# cat params.sh
#!/bin/bash
#傳參測試腳本
echo "My name is `basename $0` -I was called as $0"
echo "My first parameter is : $1"
echo "My second parameter is : $2"
空參數執行
復制代碼 代碼如下:
[root@svn shell_example]# sh params.sh
My name is params.sh -I was called as params.sh
My first parameter is :
My second parameter is :
傳遞2個參數執行
復制代碼 代碼如下:
[root@svn shell_example]# sh params.sh one two
My name is params.sh -I was called as params.sh
My first parameter is : one
My second parameter is : two
二、那如果還有參數怎么辦呢?還要一個個加上來嗎?答案是否定的
以下用法應該不陌生,就是直接執行腳本本身,沒有附帶任何參數,那么腳本講拋出幫助信息.即怎么使用此腳本.見紅字部分
復制代碼 代碼如下:
[root@svn shell_example]# sh params_v2.sh
My name is params_v2.sh -I was called as params_v2.sh
I was called with 0 parameters.
Usage: params_v2.sh first second
You provided 0 parameters,but 2 are required.
代碼如下
復制代碼 代碼如下:
[root@svn shell_example]# cat params_v2.sh
#!/bin/bash
# 這是個測試腳本傳參的測試例子
echo "My name is `basename $0` -I was called as $0"
echo "I was called with $# parameters."
if [ "$#" -eq "2" ];then
echo "My first parameter is $1"
echo "My second parameter is $2"
else
echo "Usage: `basename $0` first second"
echo "You provided $# parameters,but 2 are required."
fi
詳細的執行過程如下
不傳參數執行
復制代碼 代碼如下:
[root@svn shell_example]# sh params_v2.sh
My name is params_v2.sh -I was called as params_v2.sh
I was called with 0 parameters.
Usage: params_v2.sh first second
You provided 0 parameters,but 2 are required.
傳遞3個參數執行
復制代碼 代碼如下:
[root@svn shell_example]# sh params_v2.sh one two three
My name is params_v2.sh -I was called as params_v2.sh
I was called with 3 parameters.
Usage: params_v2.sh first second
You provided 3 parameters,but 2 are required.
傳遞2個參數執行
復制代碼 代碼如下:
[root@svn shell_example]# sh params_v2.sh one two
My name is params_v2.sh -I was called as params_v2.sh
I was called with 2 parameters.
My first parameter is one
My second parameter is two
問題來了,要是后期還要加參數怎么辦呢?或者我也不確定到底會傳幾個參數.
解決方法如下,詳細執行結果如下
復制代碼 代碼如下:
[root@svn shell_example]# cat manyparams.sh
#!/bin/bash
#這是個測試腳本傳N個參數的例子
echo "我的名字是 `basename $0` - 我是調用自 $0"
echo "我有 $# 參數"
count=1
while [ "$#" -ge "1" ];do
echo "參數序號為 $count 是 $1"
let count=count+1
shift
done
一個參數執行
[root@svn shell_example]# sh manyparams.sh one
我的名字是 manyparams.sh - 我是調用自 manyparams.sh
我有 1 參數
參數序號為 1 是 one
5個參數執行
復制代碼 代碼如下:
[root@svn shell_example]# sh manyparams.sh one two three four five
我的名字是 manyparams.sh - 我是調用自 manyparams.sh
我有 5 參數
參數序號為 1 是 one
參數序號為 2 是 two
參數序號為 3 是 three
參數序號為 4 是 four
參數序號為 5 是 five
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