設(shè)置AccessCount字段可以根據(jù)需求在特定的時(shí)間范圍內(nèi)如果是相同IP訪問(wèn)就在AccessCount上累加。
這當(dāng)然不是我們想要的，所以得換一種思路來(lái)實(shí)現(xiàn)，如下：
復(fù)制代碼 代碼如下:
declare @Year int
set @Year=2009
select
m as [Date],
sum(
case when datepart(month,AccessDateTime)=m
then AccessCount else 0 end
) as [Count]
from
Counter c,
(
select 1 m
union all select 2
union all select 3
union all select 4
union all select 5
union all select 6
union all select 7
union all select 8
union all select 9
union all select 10
union all select 11
union all select 12
) aa
where
@Year=year(AccessDateTime)
group by
m
查詢(xún)結(jié)果如下：
2 根據(jù)天來(lái)查詢(xún)，以小時(shí)為單位。這個(gè)和上面的類(lèi)似，代碼如下：
復(fù)制代碼 代碼如下:
declare @DateTime datetime
set @DateTime=getdate()
select
right(100+a,2)+ ':00 -> '+right(100+b,2)+ ':00 ' as DateSpan,
sum(
case when datepart(hour,AccessDateTime)> =a
and datepart(hour,AccessDateTime) b
then AccessCount else 0 end
) as [Count]
from Counter c ,
(select 0 a,1 b
union all select 1,2
union all select 2,3
union all select 3,4
union all select 4,5
union all select 5,6
union all select 6,7
union all select 7,8
union all select 8,9
union all select 9,10
union all select 10,11
union all select 11,12
union all select 12,13
union all select 13,14
union all select 14,15
union all select 15,16
union all select 16,17
union all select 17,18
union all select 18,19
union all select 19,20
union all select 20,21
union all select 21,22
union all select 22,23
union all select 23,24
) aa
where datediff(day,@DateTime,AccessDateTime)=0
group by right(100+a,2)+ ':00 -> '+right(100+b,2)+ ':00 '
查詢(xún)結(jié)果如下圖：
