| 字段 | 注釋 |
|---|---|
| id | 主鍵 |
| name | 商品名稱 |
| price | 價格 |
| level2 | 二級分類 |
| level1 | 一級分類 |
INSERT INTO "report2"("id", "name", "price", "level2", "level1") VALUES ('0015', '洗發露', '36', '洗護', '日用品');
INSERT INTO "report2"("id", "name", "price", "level2", "level1") VALUES ('0008', '香皂', '17.5', '洗護', '日用品');
INSERT INTO "report2"("id", "name", "price", "level2", "level1") VALUES ('0007', '薯條', '7.5', '垃圾食品', '零食');
INSERT INTO "report2"("id", "name", "price", "level2", "level1") VALUES ('0009', '方便面', '3.5', '垃圾食品', '零食');
INSERT INTO "report2"("id", "name", "price", "level2", "level1") VALUES ('0004', '辣條', '5.6', '垃圾食品', '零食');
INSERT INTO "report2"("id", "name", "price", "level2", "level1") VALUES ('0006', 'iPhone X', '9600', '小電器', '電器');
INSERT INTO "report2"("id", "name", "price", "level2", "level1") VALUES ('0003', '手表', '1237.55', '小電器', '電器');
INSERT INTO "report2"("id", "name", "price", "level2", "level1") VALUES ('0012', '電視', '3299', '大電器', '電器');
INSERT INTO "report2"("id", "name", "price", "level2", "level1") VALUES ('0016', '洗衣機', '4999', '大電器', '電器');
INSERT INTO "report2"("id", "name", "price", "level2", "level1") VALUES ('0013', '圍巾', '93', '配飾', '服裝配飾');
INSERT INTO "report2"("id", "name", "price", "level2", "level1") VALUES ('0017', '特步涼鞋', '499', '鞋子', '服裝配飾');
INSERT INTO "report2"("id", "name", "price", "level2", "level1") VALUES ('0001', 'NIKE新款鞋', '900', '鞋子', '服裝配飾');
INSERT INTO "report2"("id", "name", "price", "level2", "level1") VALUES ('0002', '外套', '110.9', '上衣', '服裝配飾');
INSERT INTO "report2"("id", "name", "price", "level2", "level1") VALUES ('0014', '作業本', '1', '紙張', '文具');
INSERT INTO "report2"("id", "name", "price", "level2", "level1") VALUES ('0005', '鉛筆', '7', '筆', '文具');
INSERT INTO "report2"("id", "name", "price", "level2", "level1") VALUES ('0010', '水杯', '27', '餐飲', '日用品');
INSERT INTO "report2"("id", "name", "price", "level2", "level1") VALUES ('0011', '毛巾', '15', '洗護', '日用品');
INSERT INTO "report2"("id", "name", "price", "level2", "level1") VALUES ('0018', '繪圖筆', '15', '筆', '文具');
INSERT INTO "report2"("id", "name", "price", "level2", "level1") VALUES ('0019', '汽水', '3.5', '其它', '零食');
select
t1.*,
case when t_rank=t_count then t_count else null end as level1_row,
case when tu_rank=tu_count then tu_count else null end as level2_row
from
(
select
*,
row_number() over(PARTITION by level1 order by level1 asc) t_rank,
count(1) over (partition by level1) t_count,
row_number() over(PARTITION by level1,level2 order by level1,level2 asc) tu_rank,
count(1) over (partition by level1,level2) tu_count
from report2 order by level1
) t1 order by t1.level1,t_rank desc,t_count desc,tu_rank desc,tu_count desc;
_紅色_部分即為前端童鞋需要的合并數值哈🥰~
如果你能看懂以上問題及求解的 sql ,恭喜你又升級啦😂
總結下::對問題的分析✨以及對問題求解的思考🤔很重要嘛，當然還包含對postgresql所提供工具的靈活使用 👉 總會產生意想不到的驚喜，哈哈😘~
到此這篇關于postgresql高級應用之合并單元格的思路詳解的文章就介紹到這了,更多相關postgresql合并單元格內容請搜索腳本之家以前的文章或繼續瀏覽下面的相關文章希望大家以后多多支持腳本之家！
