為確保php頁面在后臺運行，寫了一個監控腳本，假設程序異常退出，那么可以自動重啟。
shell腳本/usr/local/scripts/receve.sh內容：
#!/bin/bash
#funtion:keep receve.php running
PHP="/usr/local/php5/bin/php"
PROGRAM="receve.php"
#start dameo
$PHP /home/httpd/$PROGRAM >>/usr/local/scripts/phpshell/receve.out
chpid="$!";
echo "$chpid" > /usr/local/scripts/phpshell/receve.sid
echo "child pid is $chpid"
echo "status is $?"
while [ 1 ]
do
wait $chpid
exitstatus="$?"
echo "child pid=$chpid is gone, $exitstatus" >>/usr/local/scripts/phpshell/receve.php_error.log
echo `date` >> /usr/local/scripts/phpshell/receve.php_error.log
echo "**************************" >>/usr/local/scripts/phpshell/receve.php_error.log
sleep 10
$PHP /home/httpd/$PROGRAM >> /usr/local/scripts/phpshell/receve.out
chpid="$!";
echo "$chpid" > /usr/local/scripts/phpshell/receve.sid
echo "next child pid is $chpid"
echo "next status is $?"
done
需要保證監控腳本正常運行，在每天凌晨自動重啟腳本/usr/local/scripts/restart_r.sh，寫入crontab：
#!/bin/bash
echo "" >/tmp/receve_pid.txt
/bin/ps ax | /bin/grep "receve.sh" | /bin/grep -v "grep" | /bin/awk '{print $1}' >/tmp/receve_pid.txt
no1pid=`cat /tmp/receve_pid.txt | sort -r`
no2pid=`cat /usr/local/scripts/phpshell/receve.sid | sort -r`
if [ -z $no1pid ];then
echo "receve.sh pid is null, receve.sh is not running."
else
/bin/kill -9 "$no1pid"
echo "receve.sh killed"
fi
sleep 3
if [ -z $no2pid ];then
echo "receve.php pid is null, receve.php is not running."
else
/bin/kill -9 "$no2pid"
echo "receve.php killed"
fi
rm -rf /usr/local/scripts/phpshell/receve.sid
sleep 3
/usr/local/scripts/receve.sh > /dev/null
crontab：
復制代碼 代碼如下:
#restart receve.sh
10 00 * * * /usr/local/scripts/restart_r.sh
注意：腳本命名要避免重復，避免自己kill掉自己的進程。
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